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What are values of x and y ?

If a^(2x-1)=b^(1-3y), A^(3x-1)=b^(2y-2), And show that 13xy-7x-5y+3=0 Good luck needs solution urgenttt

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Answer #1

This is gonna be annoying to type up.

Let’s ‘name’ the equations first:

a^(2x-1) = b^(1-3y) …(1) a^(3x-1) = b^(2y-2) …(2)

then you have to make b (or a, but I chose b instead) the subject of (2)

b^(2y-2) = a^(3x-1)

        b = a^ [ (3x-1) / (2y-2) ] ...(3)

Then sub (3) into (1)

a^(2x-1) = b^(1-3y) a^(2x-1) = (a^[ (3x-1) / (2y-2) ])^(1-3y) a^(2x-1) = a^[ (3x-1)(1-3y) / (2y-2) ]

And since the bases are equal, the powers must also be equal

2x-1 = (3x-1)(1-3y) / (2y-2) (2x-2)(2y-2) = (3x-1)(1-3y) 4xy - 4x - 2y + 2 = 3x - 9xy - 1 + 3y 13xy - 7x - 5y + 3 = 0

There you have it. The “7th-9th grade level” problems solution.

Answer #2

dude…why dont you solve them instead of saying its complexity.. try and speak out… 2 variables and 2 equations..every one on this planet can do that.. find and show that result dude.

Answer #3

So…at 19, you should be able to do this, easily.

Equations “balance” across the equal sign, so, the value on the left of the equal sign is the same as the value on the right.

Now that you know that, it should be child’s play…in the US, those problems are considered 7th-9th grade level, at most, depending on how ahead or behind the curve the person is that’s getting the home work.

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