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Log(sub2)x+log(sub2)[x-2]=3... How do you solve that?
log(base2)(x) + log(base2)(x-2) = 3
Combine the Logs:
log(base2)(x(x-2)) = 3
Raise both sides over 2 (the base):
x(x-2) = 2^3 = 8
Put it together:
x^2 - 2x - 8 = 0
Factorise:
(x+2)(x-4) = 0
Therefore:
x = -2, or +4.
thanks...genius!