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The genius question...
A boat travels 2km upstream and 2km downstream. The total time for both parts of the trip is 1 hour. The spee of the stream is 2km per hour. What is the speed of the boat in still water?
I think the answer is 2srt2 which is 4.828427124746 thanks
using b1ff’s method, I got 4.828427124746km/h as a pretty accurate estimate :)
it is hard .,, can you show me the answer ?
what ?
4km/hr
You know the two legs of the trip take 1 hours total, so T1+T2 = 1hour.
You know the distance of each leg is 2 km, and distance is speed times time.
s=vt.
So s/v =t
Therefore you can say:
s/(v-vs) + s/(v+vs) = 1
Where vs is stream speed.
You cross multiply this or any method you like, and factorise it, so get a solution of around 4.8km/hour (ignore the negative value).
Checking 4.8km/hour:
It would take t=s/v T1=2/2.8 = 5/7
T2 = 2/6.8 = 5/17
Add them up, and you get 120/119 = 1.008 hours.
So pretty close, just find the solution of the factor more accurately than I did.
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