# Math Homework...HELP...=/

The perimeter of a rectangular playing field is not to exceed 280ft. The width is to be 20ft less than the length. What widths will meet these conditions?

OK…So I need the steps to how you get this and the answer…=/ please help…Thank you thank you thank you!!!

ya, I just did this in class, that is right

I think -

rectangle has 2 Length and 2 Width. lets say its permiter is equal to 280 (though in the question, its like less than or equal to).. for easier computation.

2L + 2W = 280 feet

the Width is said to be 20 feet less than length so W becomes (L-20). just substitute this to the W in the equation.

2L + 2(L-20) = 280 feet distribute the 2 to the items in parentheses so it becomes: 2L + 2L - 40 = 280 transpose 40 to the side of 280 (and this reverses the sign it has)

2L+2L = 280 + 40 4L = 320 L = 80

So if W = L - 20. W equals 60.

L = 80 L = 80 W = 60 W = 60

equals 280

hope I explained it alright and I hope I got it right as well.

More Like This

### Urgent Homework Help

Education, Tutoring Services, Test Preparation

### Assignment Help For You

Education, Writing Services, Tutoring

### My Homework Help

Education, Tutoring, Academic Services

### Database Homework Help

Education, Technology, Academic Support

### Top Accounting Experts Homewo...

Education, Tutoring, Academic Services