Can you help me solve this math question?

2(4a+5)+3a+3 =68

I know how to do it, but for some reason I forgot. Lol, please help me and let me know how you go the answer. Thanks!

First multiply the 2 with the stuff in the first set of parentheses:

8a+10

then add the other stuff

8a +10+3a+3=68

combine like items

11a +13 = 68

subtract 13 from each side

11a = 55

divide each side by 11

a = 5

Okay thank you, I got the same answer! Yay! Thanks once again. I got it now.

wow... I would have never figured that out. math is not my best subject. Good job nostalgique...

So...

3(2z+5)+4z=75

would end up being: 6

I got it. We just learned that today and I couldnt find my notes. But I got em now. Dont reall nedd them anymore though, once I get use to it.

Thanks!

6z+15+4z=75
10z+15=75
10z=60
z=6

Absolutely Best of luck with your homework. Glad to be of service.

beginning algebra? I love these problems.

Not quite. I use to suck at math, but now its one of my favorite classes. I love these problems too.

hey just mail me if you have any math questions because im in 8th grade and in algebra 4, so I pretty much know the ropes! I luv helping w/math so any more questions just let me know!

Okay thank you!

ok ill help you on this if you need it.
2(4a+5)+3a+3=68.
distribute the 2 into the parentheses, or-- multiply 2 times everything inside the parentheses. 2 x 4a= 8a. 2x5 =10.
8a+10+3a+3=68.
COLLECT TERMS.
8a+3a=11a
10+3=13
so, 11a+13=68
subtract 13 from each side so the variable (a) will only be on the left side.
11a+13=68
-13 -13
11a=55
divide both sides by 11 so you will get 'a' by itself.
11a=55
--- ---
11 11
a=5.

yayyy! (:

Haha, I like the yayyy! (: part! Lol. Thank you!