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First multiply the 2 with the stuff in the first set of parentheses:
8a+10
then add the other stuff
8a +10+3a+3=68
combine like items
11a +13 = 68
subtract 13 from each side
11a = 55
divide each side by 11
a = 5
Okay thank you, I got the same answer! Yay! Thanks once again. I got it now.
wow... I would have never figured that out. math is not my best subject. Good job nostalgique...
So...
3(2z+5)+4z=75
would end up being: 6
I got it. We just learned that today and I couldnt find my notes. But I got em now. Dont reall nedd them anymore though, once I get use to it.
Thanks!
6z+15+4z=75
10z+15=75
10z=60
z=6
Absolutely
Best of luck with your homework. Glad to be of service.
beginning algebra? I love these problems.
Not quite. I use to suck at math, but now its one of my favorite classes. I love these problems too.
hey just mail me if you have any math questions because im in 8th grade and in algebra 4, so I pretty much know the ropes! I luv helping w/math so any more questions just let me know!
ok ill help you on this if you need it.
2(4a+5)+3a+3=68.
distribute the 2 into the parentheses, or-- multiply 2 times everything inside the parentheses. 2 x 4a= 8a. 2x5 =10.
8a+10+3a+3=68.
COLLECT TERMS.
8a+3a=11a
10+3=13
so, 11a+13=68
subtract 13 from each side so the variable (a) will only be on the left side.
11a+13=68
-13 -13
11a=55
divide both sides by 11 so you will get 'a' by itself.
11a=55
--- ---
11 11
a=5.
yayyy! (:






Can you help me solve this math question?
2(4a+5)+3a+3 =68
I know how to do it, but for some reason I forgot. Lol, please help me and let me know how you go the answer. Thanks!