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Can you help me with these math problems?

aaah :) Asked by imprettycool0 about 1 month ago, 3 answers.

I missed a week of school because I went to Florida for vacation. And my math teacher gave me problems to do, and I'm completley lost clueless on how to do them. On the worksheet, it just says to solve each equation. And I don't know how. Here's a few...

I'd like help on;

3(2z + 25) - 2 (z - 1) = 78

And then there are 2 problems with fraction I don't know how to do;
(11/3)a - 1 = (7/11)a + 9

(2/5)x + (3/7) = 1 - (4/7)x

I'm not wanting answers. I'd just like to know how to do them.

me...deal with it Answered by roxyrumble on Sep 30, 2009, 06:17PM
614 answers

Ok you have to use the distibutative property. Then combine like terms. And subract and or divide from both sides. Need more detailed answer.

kitty Answered by ty (Online now) on Sep 30, 2009, 06:17PM
10129 answers
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3(2z + 25) - 2 (z - 1) = 78

so you open up the equation, whenever you have something outside a bracket, you multiply it with EVERY term within the bracket, so starting with the first part

3(2z + 25) = (3 x 2z) + (3 x 25) = 6z + 75
- 2 (z - 1) = (-2 x z) - (-2 x 1) = -2z - (-2) = -2z + 2

(6z + 75) + (-2z + 2) = 78

like terms together
6z - 2z = 4z
75 + 2 = 77

4z + 77 = 78
4z = 78-77
4z = 1
z = 1/4

CHECK

3 (0.5 + 25) - 2 (0.25-1) = 78
3 (25.5) - 2 (-0.75) = 78
76.5 - (- 1.5)
76.5 + 1.5 = 78
78 = 78

Lately Answered by fantastic on Sep 30, 2009, 06:28PM
75 answers

6z+75-2z+2=7

4z+75=78

4z=78-75

4z=3

z=3/4

(11/3)a - 1 = (7/11)a + 9

(11/3)a + (7/11)a = 9+1

121-21/33 a= 10

100/33 a= 10

a=10 x 33/100

a=3.3

(2/5)x + (3/7) = 1 - (4/7)x

2/5x+4/7x=1-3/7

14+20/35x=7-3/7

34/35x=4/7

x=4/7 / 34/35

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